-16t^2+70t+5.8=0

Solution for -16t^2+70t+5.8=0 equation:

-16t^2+70t+5.8=0

a = -16; b = 70; c = +5.8;
Δ = b2-4ac
Δ = 702-4·(-16)·5.8
Δ = 5271.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-\sqrt{5271.2}}{2*-16}=\frac{-70-\sqrt{5271.2}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+\sqrt{5271.2}}{2*-16}=\frac{-70+\sqrt{5271.2}}{-32}
$